Thalès\ rédaction: j'apprends\ le\ cours\ !

A

B

C

M

N

\frac {AM}{AB}=\frac {AN}{AC}=\frac {MN}{BC}

\frac {AM}{AB}=\frac {AN}{AC}=\frac {MN}{BC}\
ou\ autre\ possibilité\ valide\ aussi:\
\frac {AB}{AM}=\frac {AC}{AN}=\frac {BC}{MN}

réponse

(d)

(d)//(d')

On\ sait\ que :

les\ droites\ (BM)\ et\ (CN)\ sont\ sécantes\ en\ A

(MN)//(BC)

On\ utilise:

le\ théorème\ de\ Thalès

On\ en\ déduit\ que :

(d')

MathsEnClair.com

A = (-3.2120492660436466, 4.558120837469877)
B = (-4.273653215615012, 0.751649018286061)
C = (1.7277564993041952, 1.4689489842126595)
a = Line(A, B)
c = Line(A, C)
D = Point(a)
E = Point(c)
F = Point(c)
G = Point(a)
d = Segment(F, E)
f = Segment(G, D)
g = Line(B, C)
H = Point(f)
h = Line(H, g)
I = Intersect(h, d)
J = Point(h)
K = Point(g)
L = Point(h)
M = Point(g)
i = Segment(J, L)
j = Segment(K, M)
k = false
texte6 = LaTeX(F, true, true)
C_1 = Point(i)
R = Intersect(f, j)
S = Intersect(d, j)
T = Midpoint(R, S)
b = false
e = false
l = false
m = false